Answer:
50+50=100
100+100=200
Step-by-step explanation:
The sum of 2 numbers is 100. 50 x 2 = 100
Twice the first number plus twice the second number is 200.
50+50=100 so therfore 100+100 makes 200
i'm 85% certain the answer is C. Fiona is not correct because the coin will definitely land in the white area .
Answer: 25
Step-by-step explanation:
Both lines are being cut by the same transversal so to solve for x, make both equations equal to each other
2x+10 = 3x-15
To isolate x, do the inverse operations (for any side chosen)
Do the inverse operations to move -15 and isolate 3x
Add 15 to 10 (10+15=25)
You now have 2x+25=3x
Now, do the same to combine the x values together
25=3x-2x
You now have 25=1x
Divide by 1 on both sides
25=x
We are told to use simple interest rate. Formula for this is:
Where:
A= total accumulated amount (principal + interest)
P= principal
r= yearly percentage rate
t= number of years
We need to save $19500 for the first year at a college. This is the amount we will have at the account after five years. In our case this is A.
Principal is the amount we need to put into savings to get the total amount needed. In our case this is P.
Yearly percentage rate is the percentage by which our savings increase at the end of a year. In our case this is r.
t is number of years that we are holding our money on the bank account.
To solve this problem we will assume that we are putting same amount each month on the bank account.
We are given:
A=$19500
P=?
r=1.5%
t=5 years
First step is to transform r into decimal number:
Now we get back to our formula and we solve it for P:
We insert numbers and we get our principal:
We need to put $18139.53 into savings to get required amount after 5 years or 5*12=60months. Assuming that we put same amount each month into savings we need to put
This is our solution for this problem. This is closest to the amount we would need to put in real life. In real life we would earn interest onto interest and our monthly amount would be smaller.
C. y = 3x - 4
Step-by-step explanation:
Given coordinates:
(2, 2), (3, 5), (5, 11), (7, 17)
The equation of any straight line is
y = mx + c
Where
m = Gradient
c = Constant
Gradient = y2 - y1/x2 - x1
Substitute any two values of y with the respective values of x.
Gradient = 17 - 2/7 - 2
= 15/5
= 3
Substitute the gradient into the general formula.
y = 3x + c
Substitute any value of the coordinate to the equation
2 = 3(2) + c
2 = 6 + c
c = -4
From y = mx + c,
substitute the values of m, the gradient, and c, the constant.
y = (3)x + (-4)
y = 3x - 4