Answer:
bh/2
Meaning :
base times height, halfed
Answer:
The area of the building in terms of y in its simplest form is 12(y + 2)
Step-by-step explanation:
Since the area of a rectangle is A = LW where L = length and W = width. From our question, the width of the rectangular building is 3 feet. So, W = 3 feet and its length is 4y + 8 feet. So, L = 4y + 8 feet.
So, the area of the building in terms of y is A = LW
= (4y + 8) × 3
Factorizing out 4 from the expression, we have
= 4(y + 2) × 3
= 12(y + 2)
So, the area of the building in terms of y in its simplest form is 12(y + 2)
A)
To be similar triangles have to have equal angles
triangle ZDB'
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees
angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90
triangle ZDB'
DZB'+DB'Z=180-90=90
DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2
c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem
pass
Step-by-step explanation:
<u>G</u><u>iven </u><u>:</u><u>-</u>
- A right angled triangle with two sides 10cm and 9cm .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;
Substituting the respective values,
Simplify,
Take arcsin both sides ,
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>4</u><u>.</u><u>1</u><u>5</u><u>°</u><u> </u><u>.</u><u> </u>
