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LekaFEV [45]
3 years ago
6

12. Use a trigonometric ratio to find the measure of O in the triangle below. Give your answer to the nearest degree.

Mathematics
1 answer:
larisa [96]3 years ago
6 0

<u>G</u><u>iven </u><u>:</u><u>-</u>

  • A right angled triangle with two sides 10cm and 9cm .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of theta .

<u>Solution</u><u> </u><u>:</u><u>-</u>

At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;

\longrightarrow sin\theta =\dfrac{perpendicular}{hypotenuse}

Substituting the respective values,

\longrightarrow sin\theta =\dfrac{9cm}{10cm}

Simplify,

\longrightarrow sin\theta= 0.9

Take arcsin both sides ,

\longrightarrow \theta =sin^{-1}(0.9)

\\\longrightarrow\underline{\underline{\theta = 64.15^o }}

<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>4</u><u>.</u><u>1</u><u>5</u><u>°</u><u> </u><u>.</u><u> </u>

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