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3 years ago

Systems of equations. Y= -3x+1 Y=x-3 How do i start it

1 answer:

4 0

You can set both equations together

y = -3x + 1

and y = x - 3

we can replace the y of one equation with the other side

-3x+1 = x-3

add 3x on both sides

1 = x + 3x -3
add 3 on both sides

1 + 3 = x+ 3x

simplify

4 = 4x

divide by 4 on both sides

x = 1

y = x - 3
y = 1 - 3
y = 2

So the solution is: (1,2)

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6x - 4 = 16

Juli2301 [7.4K]

Hello!

Answer:

x=10/3

Step-by-step explanation:

First you want start by adding 4 to both sides

6x-4+4=16+4

6x=20

Then divide 6 to both sides,

6x/6=20/6

x= 10/3

Hope this helps! :)

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2 years ago

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3 years ago

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What expression is equivalent to (4-x)+3

sattari [20]

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3 years ago

Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th

Sloan [31]

Answer: $3x^2y\sqrt[3]{y}\\\\$

Work Shown:

$\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\$

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

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2 years ago

Solve for x with an explanation pls

Tatiana [17]

Answer: 9

Step-by-step explanation:

Use Pythagorean's Theorem for a right triangle.

$a^2+b^2=c^2$

$(\sqrt{63}) ^2+x^2=12^2\\63+x^2=144\\x^2=81\\x=9$

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2 years ago

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