4 years ago

Please help me I’m sorry it’s not the best pic but if u need help I can gladly tell u what they are

1 answer:

5 0

16 $x^{2}$ -1----------------(4x-1)(4x+1)

16 $x^{2}$ -4----------------4(2x+1)(2x-1)

4 $x^{2}$ -1 -----------------(2x+1)(2x-1)

4 $x^{2}$ -9-------------------(2x+3)(2x-3)

hope this helps
<3

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12. (05.02 LC) Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = 7 over q and

meriva

Answer:

$sec~y=\frac{q}{r}$

Step-by-step explanation:

$tan ~y=\frac{7}{r} \\\\\frac{sin~y}{cos~y} =\frac{7}{r} \\\\sin~y=\frac{7}{r} cos~y\\sin ~y=\frac{7}{q} \\\frac{7}{q} =\frac{7}{r} cos~y\\sec~y=\frac{7}{r} \times \frac{q}{7} =\frac{q}{r}$