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Ket [755]
3 years ago
6

Tyce hit 3/5 of the baseballs pitched to him during batting practice.Mason hit 3/4 of the number of the pitched that tyce hit. w

hat fraction of pitches did mason hit?
Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0

Answer: 9/20

Step-by-step explanation:

From the question, we are informed that Tyce hit 3/5 of the baseballs pitched to him during batting practice and that Mason hit 3/4 of the number of the pitched that tyce hit.

The fraction of pitches that Mason hit will be gotten by multiplying 3/4 by 3/5 This will be:

= 3/4 × 3/5

= 9/20

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kenny6666 [7]

Answer: 4

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5 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
Read 2 more answers
one more than six times that number is 25. select the solution and graph that represents the original number
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6n+1 = 25

subtract 1 from each side

6n+1-1 = 25-1

6n = 24

divide each side by 6

6n/6 = 24/6

n =4


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