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xxTIMURxx [149]
3 years ago
15

What is the sum and classifcation of 2/5 + square root of 18

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0
The answer to your question is going to be 65.2
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Need help on this! It is angles. What is the value of X and the measure of angle B?
Lady bird [3.3K]

Answer:

It is C.

Step-by-step explanation:

If you multiply 21 by 2 you will get, 42. If you add 16 to 42 it will equal 58. your welcome:)

4 0
3 years ago
What is the answer to math problem ×2÷3
Rashid [163]
THE answer is 0.66 repeating 9 times
then 7
5 0
3 years ago
Read 2 more answers
I need y’alls help !!
iren2701 [21]

Answer for this prob

8 0
3 years ago
Nico was stunned when he opened the mail.Here was a check for $332.50 this is the interest he earned on his investment.One year
Mazyrski [523]

Answer:

Investment A = 3650

Investment B = 1350

Step-by-step explanation:

Given that:

Total interest earned = 332.50

Total Principal invested = 5000

Investment A:

Rate = 8%

Time = 1 year

Principal = a

Interest earned = 0.08a

Investment B:

Rate = 3%

Time = 1 year

Principal = b

Interest earned = 0.03b

a + b = 5000 ____(1)

0.08a + 0.03b = 332.50 - - - (2)

From (1)

a = 5000 - b

Into (2)

0.08(5000 - b) + 0.03b = 332.50

400 - 0.08b + 0.03b = 332.50

400 - 0.05b = 332.50

-0.05b = - 67.5

b = $1350

a = 5000 - b

a = 5000 - 1350

a = $3650

7 0
3 years ago
How do you do this. Please give a full answer and explain why.
OverLord2011 [107]

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

\displaystyle \large{ {a}^{ - n}  =  \frac{1}{ {a}^{n} } }

Compare the terms.

\displaystyle \large{ {a}^{ - n}  =   {( - 2)}^{ - 3} }

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{ {( - 2)}^{ 3} } }

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

\displaystyle \large{ {a}^{3}  = a \times a \times a }

Factor (-2)^3 out.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}

(-2) • (-2) = 4 | Negative × Negative = Positive.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{4 \times ( - 2)}}

4 • (-2) = -8 | Negative Multiply Positive = Negative.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{  - 8}}

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

\displaystyle \large \boxed{ {( - 2)}^{ - 3}  =  -  \frac{1}{  8}}

The answer is - 1 / 8

3 0
3 years ago
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