All categories

3 years ago

Can y’all solve this?

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

8 0

I’m sorry if I’m wrong but 4/36=7/8?

You might be interested in

A group of students surveyed chose baseball and soccer as their favorite sport in the ratio 3:8. If 132 students were surveyed,

inysia [295]

About 50 students chose that soccer was their favorite sports. Hope it help!

5 0

4 years ago

PLEASE HELP I HAVE NO CLUE WHAT IM DOING. Parents finna ground me if I don't do this tonight.

umka21 [38]

Answer:

First find x and y at given parameters:

x = (v₀cosθ)t = (123 cos60°)t = 61.5t
y = h + (v₀sinθ)t - 16t² = 0 + (123 sin 60°)t - 16t² = 106.52t - 16t²

Maximum height is at vertex. Time is:

t = -106.52/-32 = 3.3 seconds

Maximum height is:

y = 106.52*3.3 - 16(3.3)² = 177.3 ft

Horizontal distance:

x = 61.5*3.3 = 203 feet

Time to hit the ground:

106.52t - 16t² = 0
16t = 106.52 (t = 0 is discounted)
t = 106.52/16
t = 6.7 seconds

5 0

3 years ago

Help me please! will give brainliest!

mr_godi [17]

Answer:

what is the question?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the exact area of a circle with a diameter of 5 yards. Use 3.14 for pi.

Strike441 [17]

Answer:

15.7

Step-by-step explanation:

5 0

3 years ago

The thickness X of aluminum sheets is distributed according to the probability density function f(x) = 450 (x2 - x) if 6 < x

grandymaker [24]

Solution :

Given :

$f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.$

1. Cumulative distribution function

$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$

$=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx$

$=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$

$=\frac{1}{450} \int_6^x (x^2-x) \ dx$

$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$

$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right]$

$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$

2. Mean $E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$

$=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\ dx$

$=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$

$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$

$=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) - \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right)$

$=\frac{1}{450} [4608 - 252]$

= 17.2857

5 0

3 years ago