Step-by-step explanation:
J=(x+4)²
K=(8-x)
X=5
=J+3k
=(x+4)(x+4)+3(8-x)
=(x²+8x+16+24-3x)
=25+25+40
=90
Alternatively:
J=(5+4)²
J=81
K=8-5
K=3
J+3k
81+3(3)
81+9
90
5(-5)+13=-25+13=-12
the answer would be 4n+8
hope this helps!
Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.
Yes. Slope = rise over run so you go up one, over five
