Answer:
The answer is 31 pennies
Step-by-step explanation:
we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.
The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:
1) factor: 5 (+1) = 6
6 ÷ 2 = 3 remainder 0
6 ÷ 3 = 2 remainder 0
since there is a remainder of 0, when divided by 3, 6 is wrong
2) factor; 10 (+1) = 11
11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer
3) factor : 15 (+1) = 16
16 ÷ 2 = 8 remainder 0 ( 16 is not the correct answer
4) factor : 20(+1) = 21
21 ÷ 3 = 7 remainder 0 ( 21 is wrong)
5) factor : 25(+1) = 26
26 ÷ 2 = 13 remainder 0 ( 26 is wrong)
6) factor : 30(+1) = 31
31 ÷ 2 = 15 Remainder 1
31 ÷ 3 = 10 Remainder 1
31 ÷ 5 = 6 Remainder 1
since all three divisors give a remainder of 1, the correct answer is 31
Therefore you have 31 pwnnies
Answer:
9.264817823
Step-by-step explanation:
If you use your calculator, press the log function button. Then type this (10 x 184,000,000). It will now give you your final answer.
530(1+.144/12)(.06) = 32.18 so even that is less than 35
So the answer is 31.80
Answer:
6
Step-by-step explanation:
We have two fractions and are asked to find the answer if they both are divided.
3/5 and 1/10.
When we divide fractions, we need to follow KCF
KEEP - Keep the fractions
CHANGE - Change the division sign to a multiplication sign
FLIP - Flip the second fraction
Follow :
KEEP :
3/5 / 1/10
CHANGE :
3/5 * 1/10
FLIP :
3/5 * 10/1
Now we need to multiply, which is simple because it's multiplying across :
30/5
Simplify by dividing the numerator and denominator by 5 :
Divide the numerator by denominator :
