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mylen [45]
3 years ago
11

Mora was preparing for 3 achievement assessments. She spent 3.6 hours of studying over the weekend. If she spent an equal amount

of time studying for each assessment, how much time did she spend on each assessment?
Mathematics
2 answers:
sdas [7]3 years ago
8 0
If she spent an equal amount of time studying for each, she spent 1.2 hours studying for each assessment.
Gre4nikov [31]3 years ago
7 0
1.3 hours
3.6/3 =1.3
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The total of a regular polygon's interior angles is 3420°.
DanielleElmas [232]

Step-by-step explanation:

(n-2)×180=3420

180n-360=3420

180n=3420+360

180n=3780

n=3780/180

n=21

that is, the number of sides is 21

to get the size of each exterior angle=

360/21

=17.14°

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2 years ago
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poizon [28]

Answer:

a=2.4

Step-by-step explanation:

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Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
What is the answer please
kherson [118]

The answer is (B) 2<em>k</em><em> </em>= 18

4 0
4 years ago
ASAAPPP!! Which of the following exponential equations could be represented by the table below?
Ne4ueva [31]

Answer:

Option C

Step-by-step explanation:

Just took the quiz and it was right.

7 0
4 years ago
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