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lesya692 [45]
3 years ago
7

ABCD is a quadrilateral with AB equal and parallel to DC. prove that AD is equal and parallel to BC​

Mathematics
1 answer:
rewona [7]3 years ago
6 0

Answer: see below proof

Step-by-step explanation:

Imagine a diagonal line AC

If AB = DC and AB // DC then angle BAC =

Angle ACD Alternate Interior angles theorem.

Then if AB = AD and angle BAC = angle ACD and AC = AC then triangle ABC is congruent to triangle CDA.

If triangle ABC is congruent to triangle CDA then AD = BC because congruent parts of congruent triangles are congruent.

If triangle ABC is congruent to triangle CDA then angle ACB = angle CAD because congruent parts of congruent triangles are congruent.

If angle ACB = angle CAD then AD // BC because of the alternate interior angles theorem.

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Twice the sum of a number and 5 is equal to 20
satela [25.4K]

Answer:

15

Step-by-step explanation:

Sum means the result of an addition, so 20-5=15

6 0
2 years ago
Read 2 more answers
A. In two or more complete sentences, explain how to find the exact value of sec 13pi/6 including quadrant location
Sergio039 [100]

Answer:

A. The exact value of sec(13π/6) = 2√3/3

B. The exact value of cot(7π/4) = -1

Step-by-step explanation:

* Lets study the four quadrants

# First quadrant the measure of all angles is between 0 and π/2

  the measure of any angle is α  

∴ All the angles are acute  

∴ All the trigonometry functions of α are positive

# Second quadrant the measure of all angles is between π/2 and π

  the measure of any angle is π - α

∴ All the angles are obtuse

∴ The value of sin(π - α) only is positive

  sin(π - α) = sin(α)  ⇒ csc(π - α) = cscα

  cos(π - α) = -cos(α)   ⇒ sec(π - α) = -sec(α)

  tan(π - α) = -tan(α)   ⇒ cot(π - α) = -cot(α)

# Third quadrant the measure of all angles is between π and 3π/2

  the measure of any angle is π + α  

∴ All the angles are reflex  

∴ The value of tan(π + α) only is positive

  sin(π + α) = -sin(α)  ⇒ csc(π + α) = -cscα

  cos(π + α) = -cos(α)   ⇒ sec(π + α) = -sec(α)

  tan(π + α) = tan(α)   ⇒ cot(π + α) = cot(α)

# Fourth quadrant the measure of all angles is between 3π/2 and 2π  

  the measure of any angle is 2π - α  

∴ All the angles are reflex

∴ The value of cos(2π - α) only is positive

  sin(2π - α) = -sin(α)  ⇒ csc(2π - α) = -cscα

  cos(2π - α) = cos(α)   ⇒ sec(2π - α) = sec(α)

  tan(2π - α) = -tan(α)   ⇒ cot(2π - α) = -cot(α)

* Now lets solve the problem

A. The measure of the angle 13π/6 = π/6 + 2π

- The means the terminal of the angle made a complete turn (2π) + π/6

∴ The angle of measure 13π/6 lies in the first quadrant

∴ sec(13π/6) = sec(π/6)

∵ sec(x) = 1/cos(x)

∵ cos(π/6) = √3/2

∴ sec(π/6) = 2/√3 ⇒ multiply up and down by √3

∴ sec(π/6) = 2/√3 × √3/√3 = 2√3/3

* The exact value of sec(13π/6) = 2√3/3

B. The measure of the angle 7π/4 = 2π - π/4

- The means the terminal of the angle lies in the fourth quadrant

∴ The angle of measure 7π/4 lies in the fourth quadrant

- In the fourth quadrant cos only is positive

∴ cot(2π - α) = -cot(α)

∴ cot(7π/4) = -cot(π/4)

∵ cot(x) = 1/tan(x)

∵ tan(π/4) = 1

∴ cot(π/4) = 1

∴ cot(7π/4) = -1

* The exact value of cot(7π/4) = -1

5 0
3 years ago
First to answer gets something good ;)
lesya [120]

Answer:

should be the second one 75 + 20x <55 +44x

7 0
3 years ago
mercury orbits the sun in 87 and 24/50 venus orbits the sun in 224 and 7/10 earthdays and mars orbits the sun in 686 and 49/50 d
slega [8]
Mercury: 87 24/25
Venus 224 7/10
Mars 686 49/50

All we need to do is to convert fractions so they have a denominator of 10, 100, 1000 etc.

87 24/25 = 87 96/100
224 7/10 stays the same
686 49/50 = 686 98/100

Now we can easily convert them into decimals:

Mercury: 87.96
Venus: 224.7
<span>Mars: 686.98</span>
7 0
3 years ago
Solve for qqq. 3\left(q+\dfrac43\right) = 23(q+ 3 4 ​ )=2<br>pls answer this
enyata [817]

Answer:

<h2>19/3</h2>

Step-by-step explanation:

Given the expression 3\left(q+\dfrac43\right) = 23, we are to find the value of q;

3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3

Hence the value of q is 19/3

6 0
3 years ago
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