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gulaghasi [49]
2 years ago
13

Pls answer fast pls pls

Mathematics
2 answers:
Flauer [41]2 years ago
8 0

Half of 2 percent written as a decimal is <em><u>0.01</u></em>

forsale [732]2 years ago
5 0
<h3><u>Answer</u> :- </h3>

c) 0.01

<h3><u>Solution</u> :-</h3>

To Write percentage in decimal or fraction we divide it by 100

therefore,

\begin{gathered}\\\implies\quad \sf 2\% = \frac{2}{100} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf 2\% = 0.02 \\\end{gathered}

Half of 0.02 = \sf\frac{1}{\cancel2} \times\cancel{0.02}

\implies\boxed {0.01}

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Please help I will give brainliest!
Burka [1]
Answer: the statement “measure of <4 is 105 degrees” is incorrect.

Explanation: This is because since both angles 1 and 3 are vertical, this means they are both 95. This gives us 190 (95x2). Now we subtract this from 360 which gives us 170. Since angles 2 and 4 are vertical, we divide by 2, which gives us 85, not 105.

Hope this helps! :)
3 0
3 years ago
Someone help me please
Salsk061 [2.6K]

Important notes:

3 sides 1 angle - COSINE RULE

2 sides 2 angle - SINE RULE

since, the question wants to find the length of BC. In the end we will have 3 sides and 1 angle and use cosine rule

formula of cosine rule:

a² = b² + c² - 2bc Cos A° (to find the length)

Cos A° = b² + c² - a² / 2bc ( to find the angle, if there is given three sides and have to find the angle)

So just substitute,

a² = 13² + 15² - 2(13)(15) Cos 95°

a = 20.6 or 21

5 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
PLEASE HELP!!!!!!! :/
gregori [183]
The answer is 45 when you substitute all the variables in
5 0
2 years ago
Read 2 more answers
What is the equation of a line passing through (-6, 5) and having a slope of 1/3 ? A. B. C. D. y = 3x + 7
stepan [7]

Answer:

y = 1/3 x + 7

Step-by-step explanation:

Given; the line is passing through, (-6,5) and the slope is 1/3

We can get its equation;

We would take, a point (x,y) and the given point (-6,5)

Therefore; Since slope = Δy/Δx

Then;

(5-y)/ (-6-x) = 1/3

3(5-y) = -6 -x

15 - 3y = -6 - x

we get;

3y = 6 + x + 15

3y = x + 21

Therefore;

<u>y = 1/3 x + 7</u>

3 0
3 years ago
Read 2 more answers
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