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Lubov Fominskaja [6]
4 years ago
11

Please help me, I don't understand this, I will mark brainlist 

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
8 0
16.25pi

You can get this by first solving for volume of a cylender formula for the 1.5 radius of the outer shell. Then solve for a 1 radius of the inner empty portion. Then subtract the second from the first. 
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Crazy boy [7]

Here is my answer. Hope it makes sense!

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Please answer will give brainliest to first two people
Vikentia [17]

Answer:

multiple the lenghth and weight

Step-by-step explanation:

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HELP ME PLEASE
olga_2 [115]

Answer: A (5, -5.5)

Step-by-step explanation: To find the midpoint of a line segment, you must know the formations of points. Two coordinates are made up of (x1, y1)(x2, y2). Now, to find the answer, you have to add the two x's (which is 4 and 6 = 10) and divide by 2 which equals 5. Now to find the y point, add both y's together. -5 + -6 = -11, and dividing by 2 gives you -5.5

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2 years ago
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Evaluate f(x) = 12 for the function f(x) = 5(x - 3) + 17
lara [203]

Answer:

62

Step-by-step explanation:

12-3=9

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6 0
4 years ago
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Please help! 50 points and i'll give brainliest!
lorasvet [3.4K]

Answer:

36\sqrt{3} -12\pi

Step-by-step explanation:

The area of the shaded portion, we have to calculate.

Now, join C and O to form two right triangles Δ AOC and Δ BOC.

Now, from Δ AOC,  

\tan 60 = \frac{AC}{AO} = \frac{x}{6}

⇒ x = 6√3  

So, area of Δ AOC = \frac{1}{2} \times 6 \times 6\sqrt{3}  = 18\sqrt{3}

Due to symmetry area of Δ BOC will also be 18√3.

Now, area of quadrilateral OACB is 2 × 18√3 = 36√3

Now, area covered by the arc AB about center O will be \frac{120}{360} \times \pi r^{2} = 12\pi

Therefore, the area of the shaded portion is 36\sqrt{3} -12\pi (Answer)

4 0
4 years ago
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