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vichka [17]
3 years ago
8

Someone help me plz.

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0
Answer:
20%

Explanation:
What we know:
- there are 25 cans in total
- 5 of them are root beer cans

Using this information, we can say that 5/25 cans are root beer cans. To find the percent, we change the fraction into a decimal and then multiply it by 100.

To change 5/25 into a decimal, we divide the numerator and denominator.
5/25=0.2

And we multiply the decimal by 100 to get the percent:
0.2*100=20

Therefore, 20% of Cam’s cans are root beer cans.

I hope this helps!
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Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

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The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

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The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

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<em>I'm </em><em>not </em><em>really</em><em> </em><em>sure </em><em>about</em><em> </em><em>the </em><em>answer</em><em> </em><em> </em><em>but </em><em>i </em><em>hope </em><em>it </em><em>helps </em>

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