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vichka [17]
3 years ago
8

Someone help me plz.

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0
Answer:
20%

Explanation:
What we know:
- there are 25 cans in total
- 5 of them are root beer cans

Using this information, we can say that 5/25 cans are root beer cans. To find the percent, we change the fraction into a decimal and then multiply it by 100.

To change 5/25 into a decimal, we divide the numerator and denominator.
5/25=0.2

And we multiply the decimal by 100 to get the percent:
0.2*100=20

Therefore, 20% of Cam’s cans are root beer cans.

I hope this helps!
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Step-by-step explanation:

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How do i solve this radical expression? It has to do with factoring i know that.
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Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
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b) 0.9222

c) 0.6826

d) 0.3174

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Step-by-step explanation:

Given:

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a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

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b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

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c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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