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daser333 [38]
3 years ago
15

Please help with all 3 questions and show all work thank you.

Mathematics
2 answers:
Bumek [7]3 years ago
5 0
1. 8+8=16
15+15=30
30+16=46-perimeter
15*8=120-area
2.well the slope is 3/4 but i don't know the distance
3.y(13, -6)
Sergio039 [100]3 years ago
3 0
1) Area= 120in^2. 15*8=120in^2, Perimeter= 46 2*(15+8)=46

2) 7.8102= 7.8

3) Y endpoint = 5/2 i think
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H-E-B buys cases of almonds and walnuts. Almonds are packaged 15 bags per case and walnuts are packaged 17 bags per case. H-E-B
Korvikt [17]

x is case of almonds and y is case of walnuts.

Almonds are packaged 15 bags per case and walnuts are packaged 17 bags per case.

H-E-B orders no more than 200 bags of almonds and walnuts at a time.

So,

x + y < 200

where x and y refers to the number of bags

=======================================================

H-E-B pays $24 per case of almonds and $27 per case of walnuts, but will not order more than $300 total at any one time.

But keep in mind that : Almonds are packaged 15 bags per case and walnuts are packaged 17 bags per case.

So,

24 * (x/15) + 27 * (y/17) < 300

===========================================================

The constraints are:

x + y < 200

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Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



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