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3 years ago

NEED THIS TO BE CORRECT, I WILL GIVE ANYTHING!!

Mathematics

2 answers:

skad [1K]3 years ago

6 0

Answer:

A= 87 B= 93

Step-by-step explanation:

To answer this you must have some previous conventional information. All the internal angles of a triangle summed get 180º, that means:

3(x+2)+35+52=180

3x+6+35+52=180

3x+(6+35+52)=180

3x+ 93=180 organizing the values oh the correct sides we have

3x= 180-93 ( 93 comes to the right of the =signal and changes its value from + to -.

3x=87

x=87/3 ( / stands for divided by)

x=29

Bear in mind the equation from the angle: 3(x + 2)

3( 29+ 2 )= 3x29+6=

x=87

Angle C =

3 (x + 2 )

3(29+2)=

87+6=93

JUST TO CHECK

A+B+C=180

35+52+93=180

180=180

dolphi86 [110]3 years ago

5 0

Step-by-step explanation:

3(x+2) + 35 + 52 = 180 ( Angle sum property)

3x+ 6 + 87 = 180

3x + 93 = 180

3x = 180 - 93 = 87

x= 87/ 3

x = 29

∠C = 3 ( 29 + 2)

= 3 x 31

= 93

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3 years ago

One jar of crushed ginger costs $1.99. How many jars can you buy for $17.91?

dangina [55]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: