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Digiron [165]
3 years ago
9

PLZ HELP ME 100 POINT IF U HELP ME AND GET IT RIGHT

Mathematics
2 answers:
german3 years ago
8 0
Man, I’m sorry but I really need points
ICE Princess25 [194]3 years ago
5 0

Answer:

I need the points man bit i don't know

Step-by-step explanation:

I'm stressing too

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Which two features are present in a plant cell but not in an animal cell
RoseWind [281]

Answer:

The two features present in a plant cell, but not in an animal cell are chloroplasts and a large central vacuole.

Step-by-step explanation:

8 0
3 years ago
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Help?? This question is gonna be similar to a test question tommorow i do not understand
tigry1 [53]
You should calculate( the area of a circle of radius 15 cm ) minus the area of the circle of radius (15 cm - width of the frame). I am not able to read the number, sorry. 
That is the surface area of the frame.

Then, if area of circle radius is 100%, the % of face of the clock is:

(100xareaCircle(15cm-widthframe))/areaCircle15cm


8 0
3 years ago
5/x - 3/4 =<br> Simplify
Verdich [7]

Answer:

\frac{20-3x}{4x}

Step-by-step explanation:

-This is an LCM problem.

-To simplify, we introduce a least common multiplier which is equivalent the product of the denominators:

LCM=x\times 4\\\\=4x

#We introduce the LCM and adjust the fractions based on it :

=\frac{5}{x}+\frac{3}{4}\\\\\\=\frac{20}{4x}+\frac{3x}{4x}\\\\\\=\frac{20-3x}{4x}

Hence, the simplified form of the fraction is: \frac{20-3x}{4x}

7 0
3 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
The sequence that begins with 3, where each succeeding term is twice the preceding term
Fantom [35]
What do we have  to find??

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