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3 years ago

9

PLZ HELP ME 100 POINT IF U HELP ME AND GET IT RIGHT

2 answers:

german3 years ago

8 0

Man, I’m sorry but I really need points

ICE Princess25 [194]3 years ago

5 0

Answer:

I need the points man bit i don't know

Step-by-step explanation:

I'm stressing too

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Which two features are present in a plant cell but not in an animal cell

RoseWind [281]

Answer:

The two features present in a plant cell, but not in an animal cell are chloroplasts and a large central vacuole.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help?? This question is gonna be similar to a test question tommorow i do not understand

tigry1 [53]

You should calculate( the area of a circle of radius 15 cm ) minus the area of the circle of radius (15 cm - width of the frame). I am not able to read the number, sorry.
That is the surface area of the frame.

Then, if area of circle radius is 100%, the % of face of the clock is:

(100xareaCircle(15cm-widthframe))/areaCircle15cm

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3 years ago

5/x - 3/4 =<br> Simplify

Verdich [7]

Answer:

$\frac{20-3x}{4x}$

Step-by-step explanation:

-This is an LCM problem.

-To simplify, we introduce a least common multiplier which is equivalent the product of the denominators:

$LCM=x\times 4\\\\=4x$

#We introduce the LCM and adjust the fractions based on it :

$=\frac{5}{x}+\frac{3}{4}\\\\\\=\frac{20}{4x}+\frac{3x}{4x}\\\\\\=\frac{20-3x}{4x}$

Hence, the simplified form of the fraction is: $\frac{20-3x}{4x}$

7 0

3 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

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3 years ago

The sequence that begins with 3, where each succeeding term is twice the preceding term

Fantom [35]

What do we have to find??

4 0

3 years ago