The standard form for the equation of a circle is :
<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :
((−10+(−8))/2,(1+5)/2)=(−9,3)
So the point (−9,3) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(−10−(−9))^2+(1−3)^2=1+4=5
⇒r=√5
Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :
(x+9)^2+(y−3)^2=5
The answer would be d , because you have to add how many of each fish to equal up to the sum of 420 . which is x y . so the first equation is x + y = 420 . then it says he bought 6 times as many parrotfish as he did angelfish so you would have to multiply x which represents angelfish by 6 . to get the second equation of y = 6x .
Answer:
Php2040.38
Step-by-step explanation:
Given
--- Principal
--- Rate
--- Time
--- monthly
Required
Determine the amount at the end of two years
This is calculated as:

So, we have:







<em>Hence, the final amount is: Php2040.38</em>
Answer:
Cost to arrange the event for 5 attendees will be $20.
Step-by-step explanation:
We have to solve this question by calculating the unit rates or unitary method.
Since cost to arrange corporate team building event for 3 attendees is = $12
Cost to arrange the event for 1 attendee will be =
= $4
Therefore, cost to arrange the event for five attendees will be = 5×4 = $20
Plot these points and then draw the line
X = 0
Y = -3
X = -1
Y = -2
X= -2
Y = -1