Answer: x=-1 and y=6
Steps:
So two of the equations are, " 8x+y=-2" and " -5x-2y=-7 "
8x+y=-2
8x= -2-y
x= (-2-y)/8
Now place this equation for x on the other equation.
-5 * {(-2-y)/8} -2y=-7
(10 + 5y)/8 -2y = -7
(10 + 5y - 16y)/8 = -7
10 - 11y = -7 * 8
-11y= -56 - 10
y= - 66/-11
y= 6
Now place the value of y in the first equation
8x + 6 = -2
8x= - 2 - 6
x= -8/8
x= -1
Brainliest please if I am correct!
<em>✨</em> <em>Using factorisation method</em> <em>✨</em>
Hence , option d is the correct answer
I think is closer to 4,200
Answer:
Probability both are hopelessly romantic = 0.0169
Probability at least one is hopelessly romantic = 0.2431
Step-by-step explanation:
We are given that about 1313% of the population of a large country is hopelessly romantic.
Also, given two people are randomly selected.
Firstly, Let <em>Probability that the population of a large country is hopelessly romantic = P(R) = 0.13 </em>
(a) Probability both are hopelessly romantic is given by = Probability that first person is hopelessly romantic Probability that second person is hopelessly romantic
=
= 0.13 0.13 = <u>0.0169</u>
(b) Now, Probability that the population of a large country is not hopelessly romantic = P(R') = 1 - P(R) = 1 - 0.13 = 0.87.
So, Probability at least one is hopelessly romantic is given by = 1 - Probability that none of them is hopelessly romantic
=
= 1 - (0.87 0.87)
= 1 - 0.7569 = <u>0.2431</u>