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german
2 years ago
10

Factorise a.x3+4.a.x​

Mathematics
1 answer:
Contact [7]2 years ago
4 0

Answer:

{ax}^{3}  + 4ax \\

factorise out a and x :

{ \boxed{answer{= ax( {x}^{2}  + 4) }}}\\ but \: farther \: more :  \\  = ax( {x}^{2}  +  {2}^{2} )

but from general factorization:

{ \boxed{( {a}^{2} +  {b}^{2}) =  {(a + b)}^{2}   - 2ab }}

a » x

b » 2

therefore:

= ax \{ {(x + 2)}^{2}  - 2(x)(2) \} \\  \\  = { \boxed{ \boxed{ax( {x + 2)}^{2} - 4x }}}

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Is (2,1) a solution of 3y<2x+5
Nikitich [7]

Answer:

No

Step-by-step explanation:

Plug in the x and y values and you should get 3<9

<h2><em><u>**Please rate 5 give thanks and vote brainliest**</u></em></h2>
3 0
3 years ago
Please help me I’m super confused on this problem!
Lorico [155]

Answer:

m < amc = 54°

Step-by-step explanation:

< amb and < bmc are complementary angles whose sum equals 90°.

Therefore, to find the value of 2x°, we must first solve for x.

We can establish the following equality statement:

< amb + < bmc = < amc

< 2x° + (x + 9)° = 90°

Combine like terms:

2x° + x° + 9° = 90°

3x° + 9° = 90°

Subtract 9 from both sides:

3x° + 9° - 9° = 90° - 9°

3x = 81°

Divide both sides by 3 to solve for x:

3x/3 = 81°/3

x = 27°.

Since x = 27°, substitute its value into 2x° to find m < amc:

2x° = 2(27°) = 54°

Therefore, m < amc = 54°

Please mark my answers as the Brainliest, if you find this helpful :)

5 0
2 years ago
How do you do number 16?
MA_775_DIABLO [31]
The answer to this would be 1/5. 
hope this helps
7 0
2 years ago
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