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astraxan [27]
4 years ago
11

Solve x-1/2 = x+3/-1

Mathematics
1 answer:
Goryan [66]4 years ago
8 0
First divide 3 by -1 which gives you -3 which you can add over to isolate x. After that subtract x from the left side to cancel out both xs. Since there is no x there is no solution.
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Consider the two properties that you would use to solve an equation like 3x + 5 = 26. Which of the following is true? The standa
gladu [14]
The subtraction property of equality: if we subtract one side of the equation then we also must subtract from the other side of the equation.
The division property of equality: if we divide one side of the equation by a number then we also must divide the other side by the same number.
For this equation:
3 x + 5 = 26
3 x + 5 - 5 = 26 - 5        ( the Subtraction Property of Equality )
3 x = 21
3 x : 3 = 21 : 3       ( the Division Property of Equality )
x = 7
Answer: C ) The standard method for solving an equation like 3 x + 5 = 26 is to use the Subtraction Property of Equality and then the Division Property of Equality. 
4 0
3 years ago
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the measure of ∠D is 5 times the measure of ∠E the two angles are supplemanty find the measure of each angle
hammer [34]
Because the angles are supplementary, they add to 180 degrees.

I solved this by dividing \frac{180}{6} which gives me 30 degrees.

multiply 30 by 5 gives you 150.

and 30 + 150 = 180 
3 0
4 years ago
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Please help quickly !!
anygoal [31]

Answer:

50

Step-by-step explanation:

4 0
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review the following derivation of the tangent double angle identity. the steps are not listed in the correct order. what is the
poizon [28]

The correct order of the steps used to derive the identity is a. 4,3,5,1,2.

Really talking, identification is a combination of your physical and behavioral traits that define who you are. for example, your call is part of your identity, as is the shape and color of your eyes and your fingerprint. This set of characteristics lets you be definitively and uniquely recognizable.

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8 0
2 years ago
Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 & c, d are roots of x² - 20x + 2022 then the value of ac(a
Alja [10]
<h3><u>Correct Question :- </u></h3>

\sf\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0 \: and \:  \\  \sf \: c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0 \: then \:

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =

(a) 0

(b) 8000

(c) 8080

(d) 16000

\large\underline{\sf{Solution-}}

Given that

\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0}

We know

\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}

\rm \implies\:ab = \dfrac{ - 2020}{1}  =  - 2020

And

\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}

\rm \implies\:a + b = -  \dfrac{20}{1}  =  - 20

Also, given that

\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0}

\rm \implies\:c + d = -  \dfrac{( - 20)}{1}  =  20

and

\rm \implies\:cd = \dfrac{2020}{1}  = 2020

Now, Consider

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)

\sf \:  =  {ca}^{2} -  {ac}^{2} +  {da}^{2} -  {ad}^{2} +  {cb}^{2} -  {bc}^{2} +  {db}^{2} -  {bd}^{2}

\sf \:  =  {a}^{2}(c + d) +  {b}^{2}(c + d) -  {c}^{2}(a + b) -  {d}^{2}(a + b)

\sf \:  = (c + d)( {a}^{2} +  {b}^{2}) - (a + b)( {c}^{2} +  {d}^{2})

\sf \:  = 20( {a}^{2} +  {b}^{2}) + 20( {c}^{2} +  {d}^{2})

\sf \:  = 20\bigg[ {a}^{2} +  {b}^{2} + {c}^{2} +  {d}^{2}\bigg]

We know,

\boxed{\tt{  { \alpha }^{2}  +  { \beta }^{2}  =  {( \alpha   + \beta) }^{2}  - 2 \alpha  \beta  \: }}

So, using this, we get

\sf \:  = 20\bigg[ {(a + b)}^{2} - 2ab +  {(c + d)}^{2} - 2cd\bigg]

\sf \:  = 20\bigg[ {( - 20)}^{2} +  2(2020) +  {(20)}^{2} - 2(2020)\bigg]

\sf \:  = 20\bigg[ 400 + 400\bigg]

\sf \:  = 20\bigg[ 800\bigg]

\sf \:  = 16000

Hence,

\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}

<em>So, option (d) is correct.</em>

4 0
2 years ago
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