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chubhunter [2.5K]
3 years ago
8

Please help me with this word problem...

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

10/16= 0.625,  16+0.625= 16.625

16.625*0.45=7.481kg =7481mg

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An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
3. E, F and G are collinear points. E is between F and G.
nikdorinn [45]

Answer:

<h2>A. 4 in</h2>

Step-by-step explanation:

Collinear points are points that lies on the same straight line. If the points E, F and G are collinear points, then the three points lies on the same straight line.

If E is between F and G, the FE+EG = FG

EG = FG - FE

Given FE = 3 in and FG = 7 in

On substituting into the expression above to get EG;

EG = 7in - 3in

EG = 4in

Hence the length of EG is 4in

5 0
3 years ago
Which statement is true about whether Z and B are independent events?
telo118 [61]
The answer is the first one im taking that test rn lol
3 0
3 years ago
Read 2 more answers
Graph the image of the given triangle, translated 4 units to the right and 5 units down.
LUCKY_DIMON [66]
Here the photo is attached

8 0
3 years ago
A bag contains 15 green, 18 yellow, and 16 orange balls. One ball is randomly selected.
Tcecarenko [31]

Answer:

37%

Step-by-step explanation:

total is 49

so the probability of yellow is 18/49 × 100 to get the percentage that's 36.73% to the nearest percentage is 37%

6 0
3 years ago
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