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m_a_m_a [10]
3 years ago
13

Joakim is icing 30 cupcakes. He spreads mint icing on 1/5 of the cupcakes and chocolate on 1/2 of the remaining cupcakes. The re

st will get vanilla icing. How many cupcakes have vanilla icing?
Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

Answer: 12 cupcakes have vanilla icing.

Step-by-step explanation:

 We know that Joakim is icing a total number of 30 cupcakes.

According to the exercise, Joakim spreads mint icing on \frac{1}{5} of the cupcakes.

Let be "m" the number of cupcakes that have mint icing. Then

m=(30)(\frac{1}{5})=6

He spreads chocolate on \frac{1}{2} of the remaining. The remaining is:

30\ cupcakes-6\ cupcakes=24\ cupcakes

Let be "c" the number of cupcakes that have chocolate. Then

c=(24)(\frac{1}{2})=12

Let be "v" the number of cupcakes that have vanilla icing.

Since the rest will get vanilla icing, we know that:

v=12

Sauron [17]3 years ago
7 0

Answer:

9 cupcakes.

Step-by-step explanation:

We have been given that Joakim is icing 30 cupcakes. He spreads mint icing on 1/5 of the cupcakes.  

Let us find the number of cupcakes with mint icing.

\text{Cupcakes with mint icing}=30\times \frac{1}{5}

\text{Cupcakes with mint icing}=6

We have been given that 1/2 of the remaining cupcakes have chocolate icing.

\text{Cupcakes with chocolate icing}=\frac{30}{2}

\text{Cupcakes with chocolate icing}=15

We have been given that remaining cakes have vanilla icing.

\text{Cupcakes with vanilla icing}=30-(6+15)

\text{Cupcakes with vanilla icing}=30-21

\text{Cupcakes with vanilla icing}=9

Therefore, 9 cupcakes will have vanilla icing.

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4 years ago
Jon is 3 years younger than Laura. The product of their ages is 1,330. If j represents Jon's age and j + 3 represents Laura's ag
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Trial and error method:

j and j + 3 are pretty close to each other. Start by taking the square root of 1330.

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