Answer:
An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .
and continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution
Step-by-step explanation:
An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .
continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution, continuity correction factor creates an adjustment on a discrete distribution while using a continuous distribution
Answer:
- Initial amount of the material is 67 kg
- Hal-life is 83 hours
<u>The required equation is:</u>
- m(x) = 67 *
, where m- remaining amount of the radioactive material, x - number of hours
<u>After 5 hours the material remains:</u>
- m(5) = 67 *
= 64.260 (rounded)
Answer:
First number=22
Second number=28
Step-by-step explanation:
Since you don't know either of the numbers we can call the first number x. The second number is the first number plus 6 or x+6. The sum is 22 more than the larger number so x+6+22 or x+28. Using this we can create the equation x+x+6=x+28. In order to isolate x we would subract x from both sides ending up with x+6=28. Then subract 6 from both sides to get x=22. This means the first number equals 22. Then to solve for the second number you plug 22 in for x to get the equation 22+6= the second number, so the second number is equal to 28. Look below for just the equation.
x+x+6=x+6+22
2x+6=x+28
-x -x
x+6=28
-6. -6
x=22
22+6
=28
22+28= 28+22
50=50
Hello!
You can solve this algebraically
p + n = 115
p + 4.25n = 358.75
Subtract the two equations to eliminate p
-3.25n = -243.75
Divide both sides by -3.25
n = 75
Put n into the first equation
p + 75 = 115
Subtract 75 from both sides
p = 40
The answers are,
40 pounds of peanuts were sold
75 pounds of pecans were sold
Hope this helps!
