Allied Health Professionals (AHPs) play a critical role and are the support pillars of the healthcare team. Numerous professionals are trained to handle specific health problems and provide services in their area of expertise through comprehensive assessment and diagnosis and/or treatment to promote recovery and advance quality of life. They are defined as follows:
‘Allied health professionals include individuals involved with the delivery of health or related services, with expertise contributing in therapeutic, diagnostic, curative, preventive and rehabilitative interventions. They work in interdisciplinary health teams including physicians (all medical professionals including specialists), nurses and public health officials to promote, protect, treat and/or manage a person(‘s) physical, mental, social, emotional, environmental health and holistic well-being.’
heres the website to help: https://health.economictimes.indiatimes.com/news/industry/allied-healthcare-professionals-and-their-role-in-the-healthcare-delivery-system/46835292
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Answer:
Explanation:
Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 grams, and only 25% of their eggs exceed the desired minimum weight. If a Normal model is appropriate, what would the standard deviation of the egg weights be?</em>
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<h2><em>Solution</em></h2><h2><em /></h2>
You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.
In terms of the parameters of a normal distribution that is:
- <em>mean</em> =<em> 50.1g</em> (μ)
- Area of the graph above X = 51 g = <em>25%</em>
Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25
The tables with two decimals for the Z-score show probability 0.2514 for Z-score of 0.67 and probabilidad 0.2483 for Z-score = 0.68.
Thus, you must interpolate. Since, (0.2514 + 0.2483)/2 ≈ 0.25, your Z-score is in the middle.
That is, Z-score = (0.67 + 0.68)/2 = 0.675.
Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):
Answer:C
Explanation:
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