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Llana [10]
3 years ago
5

Find the following quotients and show your work: a.6/4 divided 3/4

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0
The answer to the question is 2

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When Victoria goes bowling, her scores are normally distributed with a mean of 130
Artemon [7]

Answer:

0.2377 or about a 23.77% chance

Step-by-step explanation:

P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377

Therefore, the probability that the next game Victoria bowls, her score will be  between 123 and 130 is 0.2377 or about a 23.77% chance

5 0
3 years ago
Why is it important to look at more than the first two numbers of a pattern to decide the rule for the pattern?
Alexxandr [17]

Answer:

This is important because, the first few numbers might seem to follow a pattern but subsequent numbers might reveal a change in the rule.

Step-by-step explanation:

When studying patterns it is important to evaluate all the figures holistically instead of drawing conclusions based on just the first few numbers because there might be a change in what we felt was obvious on close observance of all the numbers. For example, observe the pattern;

2,4,6, 10, 14, 18, 20, 22, 24

The first two numbers show the addition of two. If a person decides to add 2 to all the figures, he would be wrong because after the first three figures, he would have to add 4 to the numbers.

8 0
2 years ago
The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d
aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

<h3 /><h3>Step 1</h3>

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

f(t)=\left \{ {{0 ,\-t

Consider the second function:

f(t)=\frac{e^{-t/\mu}}{\mu}\\

Where Average waiting time = μ = 2.5

The function f(t) becomes

f(t)=0.4e^{-0.4t}

<h3>Step 2</h3>

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt

which is equal to 0.01

<h3>Step 3</h3>

Solve the equation for x

\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01

Take natural log on both sides

ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0
3 years ago
Solve the inequality -5y-7&lt;28
slava [35]

Answer: IDK sssrry


Step-by-step explanation:


3 0
3 years ago
Can u answer this question the problem is below
Elodia [21]

Answer:

-3

-7

-7

-8

Step-by-step explanation:

5 0
2 years ago
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