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3 years ago

Help me please!!! its in the picture

Mathematics

1 answer:

Sonja [21]3 years ago

3 0

Hi, I'm happy to help!

First, we need to find BC. We know, because B is the midpoint of AC, that AB and BC are congruent, or the same length. We are told that AB is 3.

So, BC is 3 also.

Next, we need to find AC. AC is a combination of AB and BC, so, we just add them.

3+3=6

AC is 6.

Finally, we need to find DE. We know that AC and CE are congruent because of this sign: ≅. This means they are the same length. We can then know that CE is 6 also. To find DE we need to take the length of CD away from CE. We know that CD is 2, so now, we subtract.]

6-2=4

DE is 4.

I hope this was helpful, keep learning! :D

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Answer:

The smallest model - bottom right - in the question diagram represents $\sqrt[3]{64}=4$ .

Step-by-step explanation:

Considering the radical expression

$\sqrt[3]{64}$

Lets simply this radical expression first

$\sqrt[3]{64}$

$\mathrm{Factor\:the\:number:\:}\:64=4^3$

$=\sqrt[3]{4^3}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a,\:\quad \:a\ge 0$

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Therefore, $\sqrt[3]{64}=4$

Now, as we can determine that $\sqrt[3]{64}=4$ . So, the smallest model in the question diagram represents $\sqrt[3]{64}=4$ as each face of the cube of the smallest model in the diagram - bottom right - has 4 squares.

Therefore, the smallest model - bottom right - in the question diagram represents $\sqrt[3]{64}=4$ .

Keywords: square cube root, radical expression

Learn more about radical expression from brainly.com/question/13984232

#learnwithBrainly

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3 years ago

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2 years ago

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