Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
see below
Step-by-step explanation:
Eric will drive between 70 -4 = 66 mph and 70+4 = 74 mph. He will <em>not</em> drive less than 66 or more than 74 mph.
We are given with the function of r (x) that represents the revenue or the total sales of the company and e(x) which represents the expenses of the company. Profit, p(x), is expressed as the difference between the revenue and the sales. The answer to this problem is B.
1 and 4 will be the expression that makes the equatio. true for all values of x to prove i have done it in the picture attached in this message
