What is the equation of the line through (-2, 5) and (0, 3)? A. y = x - 3 B. y=x+3 C. y = -x + 3 D. y=-x-3

Mathematics

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

a typical line equation is the slope-intercept form

y = ax + b

"a" is the slope (always the factor of x) expressed as ratio of "y coordinate difference" / "x coordinate difference".

b is the y-intercept (the y value when x = 0).

going from (-2, 5) to (0, 3) we see

x changes by +2 (from -2 to 0).

y changes by -2 (from 5 to 3).

so the slope is -2/+2 = -1

using one of the points (0, 3) to solve for the missing b :

3 = -1×0 + b

b = 3

so, the equation is

y = -x + 3

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Can someone tell me the slope ?

borishaifa [10]

Answer:

slope = 4

Step-by-step explanation:

We can find the slope of a line when knowing 2 points by using the slope formula, $\frac{y_2 - y_1}{x_2 - x_1}$ . $x_1$ and $y_1$ represent the x and y values of the first point, respectively. $x_2$ and $y_2$ represent the x and y values of the second point, respectively.

The two points we have are (2,8) and (0,0). So, in this case, $x_1$ = 2, $y_1$ = 8, $x_2$ = 0, and $y_2$ = 0. Let's substitute those values into the formula and solve to get the slope:

$m =$ $\frac{0-8}{0-2}$