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2 years ago

What is the equation of the line through (-2, 5) and (0, 3)? A. y = x - 3 B. y=x+3 C. y = -x + 3 D. y=-x-3

Mathematics

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

a typical line equation is the slope-intercept form

y = ax + b

"a" is the slope (always the factor of x) expressed as ratio of "y coordinate difference" / "x coordinate difference".

b is the y-intercept (the y value when x = 0).

going from (-2, 5) to (0, 3) we see

x changes by +2 (from -2 to 0).

y changes by -2 (from 5 to 3).

so the slope is -2/+2 = -1

using one of the points (0, 3) to solve for the missing b :

3 = -1×0 + b

b = 3

so, the equation is

y = -x + 3

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Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

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Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

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3 years ago

What is the equation of the line through (-2, 5) and (0, 3)? A. y = x - 3 B. y=x+3 C. y = -x + 3 D. y=-x-3​

What is the equation of the line through (-2, 5) and (0, 3)? A. y = x - 3 B. y=x+3 C. y = -x + 3 D. y=-x-3