Please see attached image for the choices and proper
formatting of the problem.
What she did:
What she should have done:
The error that Eloise made in solving the radical equation
was that she subtracted 1 before squaring both sides.
<span>To add, the equation where at least one variable expression
is fixed inside a radical, usually a square root is called a radical equation.</span>
so let be the x - the cost of one night´s lodging
and let be -the y - the cost of a meal
now solve them
so x is the meal and y night spend
puting values
3 x + 6 y = 132
3 x + 2 y = 109 / * (-1)
-----------------------------
3 x + 6 y = 132
-3 x - 2 y = - 109
-----------------------
4 y = 23
solving for y
y = 5.75
now for x
3 x + 34.50 = 132
3 x = 97.50
x = 97.50 : 3
so
x = $32.50
<span>The cost of one night´s lodging is $32.50.
hope it helps</span>
<2 = 180 - 82 = 98
<3 = 50
<1 = 180- ( 98 + 50)
<1 = 180 -148
<1 = 32
answer:
<1 = 32
<2 = 98
<3 = 50
Plug in (7, 12) for x and y in the equation.
12 = 2(7) + 1
12 = 14 + 1
12 ≠ 15
Therefore, (7, 12) is not on the straight line equation.
For number 9 you just have divide the x side by -7 and then that will get y by itself.