Answer:
is the number of graph edges which touch v
Step-by-step explanation:
To find the degree of a graph, figure out all of the vertex degrees. The degree of the graph will be its largest vertex degree. The degree of the network is 5.
Once you know the degree of the verticies we can tell if the graph is a traversable by lookin at odd and even vertecies. First lets look how you tell if a vertex is even or odd.
I can’t seem to see the line below
Step-by-step explanation:
(a) If his second pass is the first that he completes, that means he doesn't complete his first pass.
P = P(not first) × P(second)
P = (1 − 0.694) (0.694)
P ≈ 0.212
(b) This time we're looking for the probability that he doesn't complete the first but does complete the second, or completes the first and not the second.
P = P(not first) × P(second) + P(first) × P(not second)
P = (1 − 0.694) (0.694) + (0.694) (1 − 0.694)
P ≈ 0.425
(c) Finally, we want the probability he doesn't complete either pass.
P = P(not first) × P(not second)
P = (1 − 0.694) (1 − 0.694)
P ≈ 0.094
A. An obtuse angle is less than 180 but greater than 90. So for examples sake I will use 179 degrees. 179 divided by 2 (as the angles are congruent) = 89.5 which is less than a right angle. Therefore, the angles will be acute.
Hope it helps :)
Answer:
a*sqrt(x+b) + c = d
or
a*√(x+b) + c = d
Step-by-step explanation:
