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uysha [10]
2 years ago
7

Given f(x) = 7xº, find f^-1 (x). Then state whether f^-1(x) is a function.

Mathematics
1 answer:
Slav-nsk [51]2 years ago
6 0

Answer:

a) (x/7)^1/9=y

Step-by-step explanation:

f(x) = 7x^9

x/7= 7y^9/7

(x/7)^1/9=(y^9)^1/9

(x/7)^1/9=y

f^-1(x) is a fuction because it passes the vl test

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Which inequality is true if p = 3.4 ?
Anastaziya [24]

Answer:

the shape isnt angled thats what it means

Step-by-step explanation:

3 0
3 years ago
Shannon poured 1 1/2 a punch into each of 5 glasses. how much total punch in cups did Shannon pour?
Arlecino [84]

Answer:

7 1/5

Step-by-step explanation:

You said that she poured 1 1/5 pouches in each cup. There are 5 cups, so multiply 1 1/5 by 5.

(e.g)

1 1/5+1 1/5= 3 because 1+1=2 & 1/2+1/2=1 so you add them and get 3

Do that twice and you get 6

then you have 1 one more cup left so add 1+6=7 then add the half 7+1 1/2=7 1/2

Your Welcome

6 0
3 years ago
Please help need to be done quickly
aalyn [17]
It’s the last one, D I guess. It’s the square root of the number surrounding x, so it’s going to be the one with the larger numbers
6 0
2 years ago
Read 2 more answers
Evaluate 4c - 5 for c = -3
Crazy boy [7]

Answer:

-17

Step-by-step explanation:

Substituting c=-3

4*-3-5

=-12-5

=-17

5 0
3 years ago
Read 2 more answers
ank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains30 gallons of water in which 5
adell [148]

Answer:

\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}

\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}

x(0)=20,y(0)=5

Step-by-step explanation:

We are given that

Tank A contains water=80 gallons

x(0)=20,y(0)=5

Tank B contains water=30 gallons

Rate=4 gallon/min

Concentration of salt  is pumped into tank=0.5 pound /gallon of water

Solution pumped from tank A to tank B at the rate=6 gallons/min

Solution pumped from tank B to tank A at the rate=2gallon/min

Solution from tank B is pumped out of the system at the rate=4 gallon/min

We have to find the DE at time t

For x

Rate in=0.5\times 4+y(t)/30\times 2

Rate in=2+y/15

Rate out=x/80\times 6

Rate out=3x/40[/tex]

\frac{dx}{dt}=Rate in-Rate out

\frac{dx}{dt}=2+y/15-3x/40

\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}

For y

Rate in=x/80\times 6

Rate in=3/40x

Rate out=y/30\times (4+2)

Rate out=y/5

\frac{dy}{dt}=Rate in-Rate out

\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}

8 0
2 years ago
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