Answer:
C. (3x2 - 10) (x - 2)
Step-by-step explanation:
3x^2 - 16x +20
Step 1: Sum = - 16x
Product = 60x^2
Step 2: Find 2 numbers that their sum is -16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and -6
Step 3: Replace -16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20
Step 4: Factorise the equation in step 3, like so;
(3x^2 - 6x)(- 10x + 20)
3x(x - 2) -10(x - 2)
(3x - 10)(x - 2)
To check if the answer is correct, expand the bracket: (3x - 10)(x - 2)
If the bracket is opened properly, you will get 3x^2 - 16x + 20
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3
Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
The answer in the simplest form : 3/4
Answer:
1,2,4
Step-by-step explanation:
<em>A chord of a circle is a straight line segment whose endpoints both lie on the circle. </em>
<em>KJ is CHORD</em><em>.</em>
<em>Tangency is point where tangent of circle touch it. </em>
<em>F is point of Tangency for FE.</em>
<em>Secant is the infinite line extension of a chord.</em>
<em>GN is a secant segment. </em>
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