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3 years ago

Explain how to compare two ratios?

Mathematics

1 answer:

djverab [1.8K]3 years ago

3 0

To compare ratios, write them as fractions. The ratios are equal if they are equal when written as fractions.

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Rag the operation signs to make the equation true. An operation may be used once. More than once, or not at all × returned to ch

-BARSIC- [3]

Answer:

12/(7-4) + 5 * 3 = 19

Step-by-step explanation:

Given

Untrue Expression: 12 ( 7 − 4 ) + 5 3 = 19

Signs: +−×÷

Required

Use the given signs to make the equation true.

To solve this, the trial and error method will be adopted.

The trial and error method involves trying series of sign combinations in the given expression; whichever works is the right answer.

So, after few attempts the following makes the equation true

12/(7-4) + 5 * 3 = 19

To check if it's true or not; we simply expand the expression on the left hand side. This gives

12/3 + 5 * 3 = 19

4 + 5 * 3 = 19

4 + 15 = 19

19 = 19.

Hence, the sign combinations used in 12/(7-4) + 5 * 3 = 19 is correct.

3 0

3 years ago

What is 384,304 estimated

Kisachek [45]

It depends what your teacher wants it rounded to. It could be 300,000 if its rounded to the hundred thousands. If it is to the nearest hundred, it would be 384,300.

7 0

3 years ago

Solve for theta <br><img src="https://tex.z-dn.net/?f=solve%20%5C%3A%20for%20%5C%3A%20%20%5Calpha%20." id="TexFormula1" title="s

nordsb [41]

I don’t know i’m sorry

6 0

3 years ago

What is the solution to the equation?

12345 [234]

2q+18=-5q-3
2q+5q=-3-18
7q=-21
q=-3

6 0

3 years ago

A school dance committee has 14 volunteers. Each dance requires 3 volunteers at the door, 5 volunteers on the floor, and 6 float

siniylev [52]

There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.

Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.

We are required to find the number of ways in which the volunteers can be assigned.

Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.

n $C_{r}$ =n!/r!(n-r)!

Number of ways in which the volunteers can be assigned is equal to the following:

Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.

Number of ways =14 $C_{12}$

=14!/12!(14-12)!

=14!/12!*2!

=14*13/2*1

=91 ways

Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.

Learn more about combinations at brainly.com/question/11732255

#SPJ1

5 0

2 years ago