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nydimaria [60]
3 years ago
11

Rationalize the denominator and simplify.

"TexFormula1" title="15 \sqrt{6}/3 \sqrt{5
" alt="15 \sqrt{6}/3 \sqrt{5
" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Bumek [7]3 years ago
3 0
(15√6 / √5)

<span>(15√6/√5) *(</span>√5/√5)

(15*√6*√5)/(√5*√5)

15*√30 / 5

3√30
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8 0
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D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



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Step-by-step explanation:

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Step-by-step explanation:

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tankabanditka [31]

Answer: How many boys want to go skating

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