Answer: C) 163
Step-by-Step Solution:
In the Right Triangle formed to the extreme right, lets mark the angles as
∠1, ∠2 and ∠3.
Therefore, from the Figure :-
∠1 = 73°
∠2 = 90°
By Angle Sum Property :-
∠3 = 180 - (73 + 90)
∠3 = 180 - 163
=> ∠3 = 17°
The Angle which forms a Linear Pair with ∠3 is the Corresponding Angle of ∠r, and Corresponding Angles are Equal.
Therefore,
=> 180 - ∠3
= 180 - 17
=> 163°
Therefore, the Angle that forms the Linear Pair with ∠3 is 163°
This Angle is Corresponding to ∠r and hence they are Equal ie. ∠r = 163°
Hence, ∠r = 163°
a. There are four 5s that can be drawn, and 
ways of drawing any three of them. There are 
ways of drawing any three cards from the deck. So the probability of drawing three 5s is
In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of 
of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability 
of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of 
.
- - -
Note: 
is the binomial coefficient,
Answer:56.8 inches
Step-by-step explanation:
For perimeter we must find the lengths of the 2 diagonal sides of the triangle which are the same because it is isosceles.
the triangle is cut directly in half so both halves of the base are 17/2
17/2 = 8.5
solve through pythagoren theorum
altitude^2 + (half of base)^2 = (diagonal length)^2
18^2 + (8.5)^2 = (diagonal length)^2
324 + 72.25 = (diagonal length)^2
396.3 = (diagonal length)^2
= diagonal length
diagonal length = 19.9
diagonal length + diagonal length + base = perimeter
19.9 + 19.9 + 17 = perimeter
56.8 inches = perimeter
you would do PEMDAS
you do -3 times 4. then you do that and devide by -3.
Answer:
17ft wide
Step-by-step explanation:
The room is 9 by 19ft
Length (x) = 19ft
Width(y) = 9ft
Area of the rug = 119ft^2
x*y = 119 ...........(1)
For the second equation we will make sure the strip around the room is uniform in size
9 - x = 19 - y
-x = 19 - 9 -y
-x = 10 - y
x = y - 10 ..........(2)
Put the value x in equation 1
(y - 10)y = 119
y^2 - 10y = 119
y^2 - 10y - 119 = 0
a = 1, b = -10, c= -119
Use quadratic formula to solve the equation
y = (-b +/-√b^2 -4ac) / 2a
y = [-(-10) +/- √ (-10)^2 - 4(1)(-119)] /2(1)
y = (10 +/- √100 + 476) /2
y = (10+/-√ 576 ) / 2
y = (10 +/- 24) / 2
y = (10 + 24) /2 or (10 - 24)/2
y = 34/2 or -14/2
y = 17 or -7
y = 17 ft
Recall that x = y - 10
x = 17 - 10
x = 7ft
