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2 years ago

Adittion of letters with powers

1 answer:

8 0

To add or subtract with powers, both the variables and the exponents of the variables must be the same. You perform the required operations on the coefficients, leaving the variable and exponent as they are.

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3 years ago

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3 years ago

. The table shows the rainfall (in inches) for three

swat32

Answer:14 the apple

Step-by-step explanation:

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3 years ago

I need help with these ASAP thanks

Nataly_w [17]

Answer:

a. $y=\frac{2x}{x-5}$

b. $y=\frac{2-4x}{x-3}$

Step-by-step explanation:

change switch x and y and then solve for y.

a. $x=\frac{5y}{y-2}$

$x(y-2)=5y$

$xy-2x=5y$

$xy-5y=2x$

$y(x-5)=2x$

$y=\frac{2x}{x-5}$

same for b.

b. $x=\frac{3y+2}{y+4}$

$x(y+4)=3y+2$

$xy+4x=3y+2$

$xy-3y=2-4x$

$y(x-3)=2-4x$

$y=\frac{2-4x}{x-3}$

4 0

3 years ago

On a farm there are three-legged-cows and chickens. There are total of 127 heads and 353 legs. How many three-legged-cows are on

olga nikolaevna [1]

Answer: There are 99 three-legged-cows and 28 chickens.

Step-by-step explanation:

Let x be the number of three-legged-cows and y be the number of chickens.

Number of legs in chicken = 2

The according to the question, we have the following equations :-

$\text{For heads }x+y=127------(1)\\\\\text{For legs }3x+2y=353------(2)$

Multiplying 2 to the equation (1), we get

$2x+2y=254--------(3)$

Now, subtract equation (3) from (2), we get

$x=353-254=99$

Put x= 99 in (1), we get

$99+y=127\\\\\Rightarrow\ y=127-99=28$

Hence, there are 99 three-legged-cows and 28 chickens.

6 0

3 years ago