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3 years ago

13. Mr. Carmello drives 30 miles each

Mathematics

1 answer:

Sauron [17]3 years ago

8 0

Answer:

240 miles

Step-by-step explanation:

he drives 30 miles there and back which is 60 miles and 6 times 4 is 24 so 60 times 4 is 240

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If a candy bar costs $0.75, how much would 4 candy bars cost?

jekas [21]

The correct answer is $3. Please mark me brainiest. :)

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3 years ago

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What is the median of this set of measurements? 10cm, 15cm, 15cm, 18cm, 20cm.

Alinara [238K]

Answer:

15 cm

Step-by-step explanation:

Median means middle number

10,15,15,18,20

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3 years ago

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Line m in xy plane contains the points (2,4) and (0,1) which of the following is the equation of M

HACTEHA [7]

Answer:

The equation of line M in slope intercept form is $y=\frac{3}{2}x+1$

The equation of line M in standard form is $3x-2y=-2$

Step-by-step explanation:

step 1

Find the slope of line M

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have the points

(2,4) and (0,1)

substitute

$m=\frac{1-4}{0-2}$

$m=\frac{-3}{-2}$

$m=\frac{3}{2}$

step 2

Find the equation of the line M in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{3}{2}$

$point\ (0,1)$

substitute

$y-1=\frac{3}{2}(x-0)$

$y-1=\frac{3}{2}x$ ----> equation in point slope form

step 3

Find the equation of line M in slope intercept form

$y=mx+b$

Isolate the variable y in the equation of the line in point slope form

$y-1=\frac{3}{2}x$

Adds 1 both sides

$y=\frac{3}{2}x+1$

step 4

Find the equation of the line M in standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=\frac{3}{2}x+1$

Multiply by 2 both sides

$2y=3x+2$

$3x-2y=-2$ ---> equation in standard form

7 0

3 years ago

Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days

zvonat [6]

Answer:

f) a[n] = -(-2)^n +2^n

g) a[n] = (1/2)((-2)^-n +2^-n)

Step-by-step explanation:

Both of these problems are solved in the same way. The characteristic equation comes from ...

a[n] -k²·a[n-2] = 0

Using a[n] = r^n, we have ...

r^n -k²r^(n-2) = 0

r^(n-2)(r² -k²) = 0

r² -k² = 0

r = ±k

a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q

We find p and q from the initial conditions.

f) k² = 4, so k = 2.

a[0] = 0 = p + q

a[1] = 4 = -2p +2q

Dividing the second equation by 2 and adding the first, we have ...

2 = 2q

q = 1

p = -1

The solution is a[n] = -(-2)^n +2^n.

g) k² = 1/4, so k = 1/2.

a[0] = 1 = p + q

a[1] = 0 = -p/2 +q/2

Multiplying the first equation by 1/2 and adding the second, we get ...

1/2 = q

p = 1 -q = 1/2

Using k = 2^-1, we can write the solution as follows.

The solution is a[n] = (1/2)((-2)^-n +2^-n).

5 0

2 years ago

Assume you have sea water that weighs 64 lb/ft³ and contains 35 parts per thousand (0.0035) dissolved salt by weight. How many c

zlopas [31]

Answer:

558.036 lb

Step-by-step explanation:

Let x is the amount of the sea water to collect 125 lb of sea salt

As given: 64 lb/ft³ has 0.0035 dissolved salt by weight

So the formula to find out the amount of the sea water is:

64 lb/ft³ * 0.0035 *x ft³ = 125 lb

<=> x = $\frac{125}{64*0.035}$ = 558.036 lb

Hope it will find you well.

7 0

3 years ago