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uranmaximum [27]
2 years ago
14

The ratio of sugar to flour used in a pudding recipe is 2:1. Which figure shows equivalent ratios? A graph is drawn. The title i

s Pudding Recipe. The axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y-axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 1,2 and 2,4 and 3,6. A graph is drawn. The title is Pudding Recipe. The axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 2,2 and 4,3 and 6,4. A graph is drawn. The title is Pudding Recipe. The x axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 2,1 and 4,2 and 6,3. A graph is drawn. The title is Pudding Recipe. The axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 2,2 and 4,4 and 6,6. Please help
Mathematics
2 answers:
liq [111]2 years ago
8 0

Answer:

The correct answer is C

Step-by-step explanation:

It is lol

Galina-37 [17]2 years ago
5 0

Answer:

idek

Step-by-step explanation:

fr

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x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −
snow_tiger [21]
For this case, what we must do is fill squares in all the expressions until we find the correct result.
 We have then:
 
 x2 + y2 − 4x + 12y − 20 = 0 x2 + y2  − 4x + 12y = 20
 x2  − 4x + y2 + 12y = 20
 x2  − 4x + (12/2)^2 + y2 + 12y  + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
 x2  − 4x + (6)^2 + y2 + 12y  + (-2)^2 = 20 + (6)^2 + (-2)^2
 x2  − 4x + 36 + y2 + 12y  + 4 = 20 + 36 + 4
 (x − 2)2 + (y + 6)2 = 60 

 
3x2 + 3y2 + 12x + 18y − 15 = 0 
 
x2 + y2 + 4x + 6y − 5 = 0 
 x2 + y2 + 4x + 6y  = 5 
 x2  + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2 
 x2  + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2 
 x2  + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9 
 (x + 2)2 + (y + 3)2 = 18 

 2x2 + 2y2 − 24x − 16y − 8 = 0
 x2 + y2 − 12x − 8y − 4 = 0
 x2 + y2 − 12x − 8y = 4 
 x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
 x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
 x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
 (x − 6)2 + (y − 4)2 = 56 

 x2 + y2 + 2x − 12y − 9 = 0
 x2 + y2  + 2x - 12y = 9
 x2  + 2x + y2 - 12y = 9
 x2  + 2x + (2/2)^2 + y2 - 12y  + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
 x2  + 2x + (1)^2 + y2 - 12y  + (-6)^2 = 9 + (1)^2 + (-6)^2
 x2  + 2x + 1 + y2 - 12y  + 36 = 9 + 1 + 36
 (x + 1)2 + (y − 6)2 = 46
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Answer:

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