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uranmaximum [27]
2 years ago
14

The ratio of sugar to flour used in a pudding recipe is 2:1. Which figure shows equivalent ratios? A graph is drawn. The title i

s Pudding Recipe. The axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y-axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 1,2 and 2,4 and 3,6. A graph is drawn. The title is Pudding Recipe. The axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 2,2 and 4,3 and 6,4. A graph is drawn. The title is Pudding Recipe. The x axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 2,1 and 4,2 and 6,3. A graph is drawn. The title is Pudding Recipe. The axis label is Sugar in cups. The x axis values are 0, 2, 4, 6, 8, 10, 12. The y axis label is Flour in cups. The y axis values are 0, 1, 2, 3, 4, 5, 6. Points are plotted on the ordered pairs 2,2 and 4,4 and 6,6. Please help
Mathematics
2 answers:
liq [111]2 years ago
8 0

Answer:

The correct answer is C

Step-by-step explanation:

It is lol

Galina-37 [17]2 years ago
5 0

Answer:

idek

Step-by-step explanation:

fr

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A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat
Nesterboy [21]

Complete Question

A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.

Write and solve an equation to find the weights of the cat and the dog.

Answer:

Weight of cat = x = 12 pounds

Weight of Dog = y = 34 pounds

Step-by-step explanation:

Let's represent:

Weight of cat = x

Weight of Dog = y

A dog weighs 2 pounds less than 3 times the weight of a cat.

y = 3x - 2........ Equation 1

The dog weighs twenty two more pounds than the cat

y = x + 22....... Equation 2

The equation is given as:

y = y

3x - 2 = x + 22

Collect like terms

3x - x = 22 + 2

2x = 24

x = 24/2

x = 12 pounds

Solving for y using any of the equations:

y = 3x - 2

y = 3 × 12 - 2

y = 36 - 2

y = 34 pounds

Therefore:

Weight of cat = x = 12 pounds

Weight of Dog = y = 34 pounds

6 0
2 years ago
Giving out 60 points
Yuki888 [10]
If the markers are 4.5 inches away on the map, and 2.5 inches represents 10 miles, then we need to make ratios we can work with.

Inches / Miles: 

4.5 / x
2.5 / 10

Now, we can cross multiply to end up with:

2.5 * x = 4.5 * 10

Simplify:

2.5x = 45

Divide 2.5 on each side:

2.5x / 2.5 = 45 / 2.5

Simplify:

x = 45 / 2.5
x = 18

Awesome! Now we have a real ratio on the real distance of the markers.

<span>2.5 : 10  &  4.5 : </span><span>18.
</span>
18 miles is the actual distance between the two markers.

Hope I could help! If my math is wrong, or it isn't the answer you are looking for, please let me know!
<span>Have a good one!</span>
6 0
3 years ago
Which expressions are less than 610
Lady bird [3.3K]

Answer:

Step-by-step explanation:

7 0
3 years ago
Plutonium-240 decays according to the function L where o
PIT_PIT [208]

Answer:

\boxed{\textbf{1700 yr}}

Step-by-step explanation:

-\dfrac{\text{d}L}{\text{d}t} = kL\\\\\dfrac{dL}{L}=-kdt\\\\\ln L = -kt + C\\\text{At t = 0, L = L$_{0}$, so C = $\ln L_{0}$}\\\ln L = -kt + \ln L_{0}\\\ln L_{0} - \ln L = kt\\\\\ln \dfrac{L_{0}}{L} =kt

Data:

L₀ = 24 g

L = 20 g

k = 0.000 11 yr⁻¹

Calculation:

\ln \dfrac{24}{20} =0.000 11t\\\\\ln 1.2 = 0.000 11t\\\\0.1823 = 0.000 11t\\\\t = \dfrac{0.1823}{0.000 11} = \textbf{1700 yr}\\\\\text{It will take } \boxed{\textbf{1700 yr}}\text{ for the polonium to decay to 20 g}

8 0
3 years ago
Hey, do you mind helping me?<br><br><br> what are the roots of x in -10x + 12x - 9 = 0?
Alex73 [517]

Answer:

x=−6±3√5

Step-by-step explanation:

3 0
3 years ago
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