3 years ago

Simplify. 42+25 A.21 B.29 C.41 D.51

1 answer:

8 0

Im actually pretty sure its C because 4 to the power of 2 is 16 and then add those too up 16+25=41

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nignag [31]

Answer: $\sqrt[3]{125x^3}$ .

Step-by-step explanation: Given radical expression

$\sqrt[3]{5x} \times \sqrt[3]{25x^2}$ .

According to the product property of roots.

$\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}$

On applying above rule, we get

$\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}$

5 × 25 = 125 and

$x \times x^2 = x^3$

Therefore,

$\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}$

<h3>So, the correct option would be second option $\sqrt[3]{125x^3}$ .</h3>

3 0

2 years ago

Lelechka [254]

Answer:

Step-by-step explanation:

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3 years ago

ASHA 777 [7]

24➗2.88=0.8 30➗0.8 = 3.75 So the answer is 3.75

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2 years ago

alexandr1967 [171]

for this i am working on this um please wait

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2 years ago

labwork [276]

$\begin{array}{ccccccccccc}x&|&-2&|&\boxed0&|&1&|&3&|&6\\-&-&-&-&-&-&-&-&-&-&-\\y&|&1&|&\boxed3&|&4&|&2&|&0\end{array}\\.\\\\\boxed{f(0)=3}$

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2 years ago