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k0ka [10]
3 years ago
6

Simplify. 42+25 A.21 B.29 C.41 D.51

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

Im actually pretty sure its C because 4 to the power of 2 is 16 and then add those too up 16+25=41

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Valor de expresión numérica 4÷3-8+7÷2-10+2÷6​
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-12.833 OR -77/6

Step-by-step explanation:

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2 years ago
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ATCs are required to undergo periodic random drug testing.
aleksandr82 [10.1K]

Answer:

The responsess to the given question can be defined as follows:

Step-by-step explanation:

P(medication\ used) = 0.007 \\\\P( drug \not\ used ) = 1 - 0.007 = 0.993\\\\P(test\ positive  | medication \ used) = 0.96 \\\\ P(test \ negative | medication \ used) = 1 - 0.96 = 0.04\\\\

P(Point | Non-used\ medication )=0.93\\\\ P(Point |No\ medication ) = 1 - 0.93 = 0.07

As per the given info we draw the tree diagram which is defined in the attachment file.

P ( test \ is\  positive ) = P( medication \ used ) \times P( Test \ positive | medication \ used ) + P( medication not \ used ) \times  P( Test\ positive | medication \ not \ used )

                  = ( 0.007 \times 0.96 ) + ( 0.993\times 0.07 )\\\\= 0.0762

P( medication \ used | test\ positive )= \frac{\textup{P( medication used ) *P( Test positive given medication  used )}}{\textup{P( medication used )}}  

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8 0
2 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

\frac{3}{8}*\frac{2}{6}*\frac{4}{8}*\frac{5}{12}\\\\\frac{3}{8}*\frac{1}{3}*\frac{1}{2}*\frac{5}{12}\\\\\frac{1}{8}*\frac{1}{3}*\frac{1}{2}*\frac{5}{4}\\\\\frac{5}{192}

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Sphinxa [80]
1) Answer: The part of the quadratic formula tells us whether the quadratic equation can be solved by factoring is b^2-4ac

2) 4x^2+6x+2=0
ax^2+bx+c=0; a=4, b=6, c=2
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Answer: b^2-4ac=4
7 0
3 years ago
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