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RUDIKE [14]
3 years ago
10

CINDY made costume decorations. She used 1/10 of a meter of ribbon for each decoration which she got by cutting 3/10 of a meter

of ribbon into equal pieces. How many decorations did CINDY make?
Mathematics
2 answers:
ivann1987 [24]3 years ago
5 0

Answer:

CINDY made 3 decorations

Step-by-step explanation:

CINDY used 3/10 of a meter of ribbon for all the decorations

I.e. Total length of ribbon used = 0.3 meters

She used 1/10 of a meter of ribbon for each decoration

I.e. Length of ribbon used for 1 decoration = 0.1 meters

Number of decorations made = (Total length of ribbons used)/(Length of           ribbon used for 1 decoration)

Number of decorations = 0.3/0.1

Number of decorations = 3

Brilliant_brown [7]3 years ago
3 0

Answer:

Cindy made 3 decorations with the ribbons

Step-by-step explanation:

Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.

If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10

i.e 3/10 ÷ 1/10

= 3/10 × 10/1

= 3 decorations.

That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).

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3 years ago
If A+D=117kg , A+M=88kg and M+D=161kg whats there total weight<br><br>thx in advance
garri49 [273]
Think of A as a constant - with D it's 117 and with M it's 88

So the difference between D and M is 29   (117-88)

We also know that M + D = 161

Let's substitute in the problem  We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161  or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88   A + 61 - 88   Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
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6 0
3 years ago
Read 2 more answers
Find the area of the region under the graph of the function f on the interval
vlada-n [284]

Answer:

9/2

Step-by-step explanation:

this is a simple integral function

given limits of interval [a,b] of a continuous function f(t), you can find the area under the curve by using:

\int\limits^a_b {f(t)} \, dt

\int\limits^3_0 {3x-x^2} \, dx

using the fundamental theorem of calculus that states the integral of f(x) in the interval [a,b] is  = g(a)-g(b), where g(x) is the antiderivative of f(x)

our g(x) = \frac32x^2-\frac13x^3

g(3)-g(0) = g(3) = 27/2 - 27/3 = 27/2-9 = 9/2

8 0
3 years ago
Elena collects 112 specimens of beetle and records their lengths for an ecology research project. When she returns to the labora
pantera1 [17]

Answer:

The correct option is;

C. She should go back and remeasure all of her specimens again to find the error. If she can't do this, she should eliminate the outlier from the analysis, because this is an error in recording

Step-by-step explanation:

In order to minimize error in measurement, some valuable steps includes;

1) Perform a double check on all measurements to ensure that the measurements recorded are accurate

2) Ensure proper training before taking measurements

3) Measurements should only be taken under controlled conditions

4) Separate the entire population into smaller groups for proper recording

5) Have a second observer double check the records

7 0
2 years ago
Which unit rate corresponds to the proportional relationship shown in the graph
Ray Of Light [21]

Answer:

5/4 8.10.............0.0 5=7=9

3 0
2 years ago
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