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Juli2301 [7.4K]
3 years ago
10

What is the solution to the equation x + 14 = 63? (Input a whole number only.) (3 points) Blank 1:

Mathematics
1 answer:
Alex3 years ago
7 0

Hey there!

This is a one-step equation, meaning that we can solve it in one step.

This is the step:

  • Subtract 14 from both sides

Goal:

  • To find out the value of x

Subtract 14:

x+14-14=63-14

the 14's on the left cancel:

x=49

Hence, the answer is

\boxed{\boxed{\bold{x=49}}}

Hope everything is clear.

Let me know if you have any questions!

#LearningDoesn'tEnd

:-)

\rule{200}{2}

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Answer:

The dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

Step-by-step explanation:

The first step will be to find the diagonal of the rea life mural.

We can use Pythagoras' Theorem to do this.

Diagonal = \sqrt{15^2 +45^2 } =47.43 feet.

Now we have the real-life diagonal, we will now relate the diagonal of the painting outside with the one on paper. We can do this by dividing the two diagonals.

This will be 47.43 / 6.3 units = 7.53.

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To get the dimensions of the length and the breadth on paper, we divide the outside dimensions by the scale factor.

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The balance on a car loan after 4 years is $8,996.32. The interest rate is 5.6% compounding annually. What was the initial value
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A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a​ single-strand electric
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Answer:

The largest area is 125000 m²

The dimensions of the farmland are 250 m and 500 m

Step-by-step explanation:

* Lets pick the information from the problem

- The farmland is shaped a rectangle

- The farmland will be bounded on one side by a river

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- Lets consider the width of the rectangle is x and the length is y

- The side which will be bounded by the river is y

∴ The perimeter of the farmland which will be bounded by the electric

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∵ The length of the wire is 1000 m

∵ The perimeter of the farmland is equal to the length of the wire

∴ 2x + y = 1000

- Lets find y in term of x

∵ 2x + y = 1000 ⇒ subtract 2x from both sides

∴ y = 1000 - 2x

- Now lets find the area can enclose by the wire

∵ The area of the rectangle = length × width

∵ The width of the farmland is x and its length is y

∴ The area of the farmland (A) = x × y = xy ⇒ (2)

- Use equation (1) to substitute the value of y in equation (2)

∴ A = x (1000 - 2x) ⇒ simplify

∴ A = 1000 x - 2 x²

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* Lets revise the rule of differentiation

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- If y = ax, then dy/dx = a

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∵ A = 1000 x - 2 x² ⇒ (3)

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∴ dA/dx = 1000 - 4x

- Put dA/dx = 0 to find the value of x

∵ 1000 - 4x = 0 ⇒ add 4x to both sides

∴ 1000 = 4x ⇒ divide both sides by 4

∴ 250 = x

∴ The value of x is 250

- Lets substitute this value in equation 3 to find the largest area

∵ A = 1000 x - 2 x²

∴ A = 1000 (250) - 2(250)² = 125000 m²

* The largest area is 125000 m²

∵ The width of the farmland is x

∵ x = 250

∴ The width of the farmland = 250 m

- Substitute the value of x in the equation (1) to find y

∵ y = 1000 - 2x

∵ x = 250

∴ y = 1000 - 2(250) = 1000 - 500 = 500

∵ The length of the farm lend is y

∴ The length of the farm land = 500 m

* The dimensions of the farmland are 250 m and 500 m

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