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3 years ago

A sphere has a radius of 3.5 inches.

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

Answer:

V≈179.59in^3

Step-by-step explanation:

4/3 πr3 if the formula

denis23 [38]3 years ago

3 0

Answer:

The volume of the sphere is 113.0in^3.

OMG IM SO SORRY, i did it for 3 in not 3.5 im so sorry

Step-by-step explanation:

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Month 1: 93 in

Elodia [21]

Answer:

9.5 inches per month

Step-by-step explanation:

Given the information about the depth of the pond:

Month 1: 93 in

Month 2: 98 in

Month 3: 112 in

From month 1 to month 3, the average rate of change of the depth of the pond, in inches per month can be calculated using formula

$\dfrac{\text{Depth}_3-\text{Depth}_1}{3-1}$

Hence, from month 1 to month 3, what is the average rate of change of the depth of the pond, in inches per month is

$\dfrac{112-93}{3-1}=\dfrac{19}{2}=9.5\ in/month$

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3 years ago

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Andre45 [30]

Answer:

Step-by-step explanation:

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2 years ago

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Ancient Egyptians did not write the fraction 4/5 as 4/5. Instead they used unit fractions. The numerator of a unit fraction is a

Salsk061 [2.6K]

3/4 = 1/2 + 1/4

5/8 = 1/2 + 1/8

7/12 = 1/2 + 1/12

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2 years ago

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77julia77 [94]

Answer:

What?

Step-by-step explanation:

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3 years ago

An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made

Lemur [1.5K]

Answer:

The dimension of box= $2ft\times 2ft\times 1ft$

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box= $lbh=x^2h$

$4=x^2h$

$h=\frac{4}{x^2}$

Now, surface area of box,A= $x^2+4xh$

$A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}$

$\frac{dA}{dx}=2x-\frac{16}{x^2}$

$\frac{dA}{dx}=0$

$2x-\frac{16}{x^2}=0$

$2x=\frac{16}{x^2}$

$x^3=8$

$x=2$

$\frac{d^2A}{dx^2}=2+\frac{32}{x^3}$

Substitute x=2

$\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0$

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

Height of box,h= $\frac{4}{2^2}=1 ft$

Hence, the dimension of box= $2ft\times 2ft\times 1ft$

5 0

2 years ago