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3 years ago

5

What are the common factors of 207 and 184

1 answer:

S_A_V [24]3 years ago

8 0

184: 2 2 2 23
207: 3 3 23
GCF: 23

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If Kendra started working at 10:13 a.m. and left at 6:15 p.m.

Roman55 [17]

8 hours 2 minutes. if you add 8hours to 10:13 you get 6:13 then just add 2 minutes and you will have 6:15 p.m

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3 years ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2y x {}^{ - 4} }{2x {}^{ - 13} y {}^{ - 9} }$

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$= \frac{x {}^{9} }{y {}^{8} }$

12.

$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4} n {}^{ - 1} }{m {}^{ - 5}n {}^{3} } = - 2m {}^{9} n {}^{ - 4}$

$= - \frac{2m {}^{9} }{n {}^{4} }$

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$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

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$- \frac{x {}^{15} }{ {y}^{6} }$

15.

$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

$- \frac{ - y {}^{4} x {}^{4} z {}^{ - 4} }{ {z}^{4} y {}^{8} } = - y {}^{4} x {}^{4} z {}^{ - 8} = - \frac{(xy) {}^{4} }{ {z}^{8} }$

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$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

6 0

2 years ago

I’m a bit stuck on this question...

lapo4ka [179]

Answer:

It's C :)

Step-by-step explanation:

The vertical line test is drawing lines on the function

4 0

3 years ago

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What is the product?<br> (2x-1)(x+4)<br> 2x²-4<br> 0<br> 2x²+4<br> 0<br> 2x² + 7x-4<br> 2x² – 7x-4

vladimir2022 [97]

Answer:

C) 2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

3 0

3 years ago

Read 2 more answers

What expression is equivalent to 1/3(4-5x-1)?

Serhud [2]

1/3( 4 - 5x - 1)

= (1/3)(4 + - 5x + - 1)

= (1/3)( 4) + (1/3)(- 5x) + (1/3)( - 1)

= 4/3 + - 5x/3 + - 1/3

= - 5x/3 + 1 (Decimal: - 1.666667x + 1)

Hope that helps!!!!

3 0

3 years ago

Read 2 more answers