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professor190 [17]
4 years ago
11

Alicia is sewing a rectangle bedspread that measures 72 inches by 60 inches. The bedspread is red with a gold circle 18 inches i

n diameter in the center. To the nearest square inch, what is the area of the bedspread that is red?
Mathematics
1 answer:
Natalija [7]4 years ago
5 0

Answer:

4,066\ in^{2}

Step-by-step explanation:

we know that

The area of the bedspread that is red is equal to the area of rectangle minus the area of the circle

step 1

Find the area of rectangle

The area is equal to

A=72*60=4,320\ in^{2}

step 2

Find the area of the circle

A=\pi r^{2}

we have

r=18/2=9\ in ----> the radius is half the diameter

assume

\pi=3.14

substitute

A=(3.14)(9)^{2}

A=254.34\ in^{2}

step 3

Find the area of the bedspread that is red

Find the difference of the areas

4,320\ in^{2}-254.34\ in^{2}=4,066\ in^{2}

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vesna_86 [32]

Answer:

P = 0.55   or  55 %

Step-by-step explanation:

First step:  Fred has probability of 0,5 when chossing jar 1 or jar 2

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Then the probability of Fred to get a chocolate chip cookie is

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3 years ago
The distance from the centroid of a triangle to its vertices are 16cm, 17cm, and 18cm. What is the length of the shortest median
Marizza181 [45]

Answer:

24 \text{cm}

Step-by-step explanation:

Given: The distance from the centroid of a triangle to its vertices are 16\text{cm}, 17\text{cm}, and 18\text{cm}.

To Find: Length of shortest median.

Solution:

Consider the figure attached

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Also,

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length of \text{AG} =16\text{cm}

length of \text{BG} =17\text{cm}

length of \text{CG} =18\text{cm}

as centrod divides median in ratio of 2:1

length of \text{AD} =\frac{3}{2}\text{AG}

                                              =\frac{3}{2}\times16

                                              =24\text{cm}

length of \text{BE} =\frac{3}{2}\text{BG}

                                              =\frac{3}{2}\times17

                                              =\frac{51}{2}\text{cm}

length of \text{CF} =\frac{3}{2}\text{CG}

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                                              =27\text{cm}

Hence the shortest median is \text{AD} of length 24\text{cm}

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In ∆ABC, if the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively, what are m <
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angle B:
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