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professor190 [17]
3 years ago
11

Alicia is sewing a rectangle bedspread that measures 72 inches by 60 inches. The bedspread is red with a gold circle 18 inches i

n diameter in the center. To the nearest square inch, what is the area of the bedspread that is red?
Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

4,066\ in^{2}

Step-by-step explanation:

we know that

The area of the bedspread that is red is equal to the area of rectangle minus the area of the circle

step 1

Find the area of rectangle

The area is equal to

A=72*60=4,320\ in^{2}

step 2

Find the area of the circle

A=\pi r^{2}

we have

r=18/2=9\ in ----> the radius is half the diameter

assume

\pi=3.14

substitute

A=(3.14)(9)^{2}

A=254.34\ in^{2}

step 3

Find the area of the bedspread that is red

Find the difference of the areas

4,320\ in^{2}-254.34\ in^{2}=4,066\ in^{2}

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○ B) 624π mm.²

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What represents 60=5 x 12?
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Step-by-step explanation:

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8 0
3 years ago
1. A sine function has the following key features:
andrew11 [14]
Problem 1

See the attached image (figure 1)

16pi seems like a typo. I'm going to assume that it's a fraction and it is 1/(6pi)
f = 1/(6pi) = frequency
T = 1/f = 1/(1/(6pi)) = 6pi
Amplitude = 2
a = 2
b = 2pi/T = 2pi/(6pi) = 1/3
Midline: y = 3
d = 3

The function is
y = a*sin(bx-c)+d
y = 2*sin(1/3*x-0)+3
y = 2*sin(x/3)+3

===============================================

Problem 2

See the attached image (figure 2) 

T = 12 is the period
a = 4 is the amplitude
b = 2pi/T = 2pi/12 = pi/6
y = 1 is the midline so d = 1
The y intercept is (0,1) which is the midline, which indicates no phase shifts have occurred so c = 0

The function is
y = a*sin(bx-c)+d
y = 4*sin((pi/6)x-0)+1
y = 4*sin((pi/6)x)+1

===============================================

Problem 3

See the attached image (figure 3)

Period = 4pi
T = 4pi
b = 2pi/T = 2pi/(4pi) = 1/2 = 0.5
Amplitude = 2
a = 2
Midline: y = 3
d = 3
y-intercept: (0,3)
The function is a reflection of its parent function over the x-axis, so 'a' is negative meaning a = -2 instead of a = 2

The function is
y = a*sin(bx-c)+d
y = -2*sin(0.5x-0)+3
y = -2*sin(0.5x)+3

===============================================

Problem 4

See the attached image (figure 4)

a = 10 which is half of the distance between the highest and lowest points
T = 8 is the period
b = 2pi/T = 2pi/8 = pi/4
c = -pi/2 is the phase shift since its really a cosine graph
d = 0 is the midline

The function is
y = a*sin(bx-c)+d
y = 10*sin((pi/4)*x+(-pi/2))+0
y = 10*sin((pi/4)*x+pi/2)

===============================================

Problem 5

See the attached image (figure 5)

a = 2 is the amplitude since it bobs up and down this distance from the midline
T = 8 seconds is the period (double that of the time it takes for it to go from the highest to the lowest point)
b = 2pi/T = 2pi/8 = pi/4
c = 0 is the phase shift as the buoy starts at normal depth of 20 meters
d = 20 is the midline

The function is
y = a*sin(bx-c)+d
y = 2*sin((pi/4)x-0)+20
y = 2*sin((pi/4)x)+20

===============================================

8 0
3 years ago
Read 2 more answers
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