Question

Math question please show work for brainliest :)

Answer 1

Hey there!!

Problem given :

3 I x - 1 I ≥ 12

Divide 3 on both sides

I x - 1 I ≥ 4

Now, in order to remove the modulus , you add a ± symbol on the other side and you need to switch the symbol for the negative values

Now,

( x - 1 )  ≥ ±4

Let's take negative first

x - 1 ≤ -4

x ≤ -3 ( this is one of the answer )

Now, lets take the positive sign

x - 1 ≥ 4

x ≥ 5

Hence, the two values are x ≤ - 3 and x ≥ 5

Hope my answer helps!