(2X-3)(4-3X)
=8X-6X²-12+9X
=-6X²+17X-12
That's your answer.
You have to give the problem and not just the options for me to solve
Yi left a factor of 63, that is 21.
So the GCF will be 21
energy is always transformed from one form to another
energy is not created nor destroyed
so when a car starts moving the chemical potential energy of the car is converted to kinetic energy
kinetic energy is the energy that moving objects possess
kinetic energy formula is as follows
Kinetic energy = 1/2 mv²
where m - mass
v - velocity
substituting these values
K.E = 1/2 x 1350 kg x (12 m/s)²
= 1/2 x 1350 x 144 = 97200 J
the kinetic energy of the car is 97.2 kJ
Hello :
x²-x-2 = (x+1)(x-2)
x²-x-2 = 0 : x+1 =0 or x-2 = 0
x= -1 or x= 2 are the zero of f(x)
