3t3t3 =9 5t5t5 = 15 add to of the products and get 105
Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
<em>f</em>
<em> t</em>
<em> t</em>
<em> t</em>
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f <em>f</em> f
f <em>t</em> t
t <em>t</em> f
t <em>t</em> t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
<em>f f </em>
<em> t t</em>
<em> t t</em>
<em> t t</em>
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
7) (12 + 6)/(2 +4)
(18)/(6) = 3
8) (42 - 24)/6
(18)/6 = 3
9) (9 + 16) - (2 x 4)
25 - 8 = 17
10) 60 - (3 + 2) x 5
60 - 5 x 5
60 - 25 = 35
11) 18 + (9/3)
18 + 3 = 21
12) 5 x (2 + 4 + 3)
5 x (9) = 45
hope this helps
Answer: you end up at (2,2)
Step-by-step explanation:
