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Vlad1618 [11]
4 years ago
13

Which equation is equivalent to –k + 0.03 + 1.01k = –2.45 – 1.81k

Mathematics
1 answer:
Nat2105 [25]4 years ago
8 0
-k + 0.03 + 1.01K = -2.45 - 1.81k
0.01k + 0.03 = -2.45 - 1.81k
0.01k + 1.81k = -2.45 - 0.03
1.82k = -2.48
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denis23 [38]
57.3333 the three is infinite
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2 years ago
Each day of the week mrs uses 3/4 of a gallon of gas what is the amount she uses in five days?
Andrej [43]

Answer:

3.75

Step-by-step explanation:

3/4 times 5 =3 3/4

8 0
1 year ago
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
What is the area of the real object that the scale drawing models?
Kruka [31]

Answer:

HOPE THIS HELPS!!

Step-by-step explanation:

YOU could find it by doing these steps:

Atual Area = ���� square units.

Scale Drawing Area = �� square units.

Value of the Ratio of the Scale Drawing Area to the Actual Area:

7 0
3 years ago
Any One Know This One
oksian1 [2.3K]

Answer:

no solutions

Step-by-step explanation:

4 + 5m = 4m + 1 + m <em>combine like terms</em>

4 + 5m = 5m + 1 <em>subtract 5m from each side</em>

4 = 1

4 can never equal 1, so no value of m would allow the equation to be correct

4 0
4 years ago
Read 2 more answers
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